11. Calculați media geometrică a numerelor: a) a = √(1-√3)² +4-√3; b) a= 3-√(√5 −3√₂)² + √18; c) a= √(√3-√6)² + √3−1; d) a = a = √7−3+√(√7+3)² +12; b= 2√/(2√2-3)* +2(3+2√/2); b = 3−|√7 -√20|-√(√5 -√7); b= V(2V3 +Vô –VIZ+L b= |2–v5 – V (V5–3) — 20+13. urgent ofer 40 de puncte!!!!!!​

Răspuns:

a) mg (a,b) = 6

b) mg (a,b) = 2

c) mg (a,b) = √5

d) mg (a,b) = 12

Explicație pas cu pas:

mg (a,b) = √(a·b)

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a) a = √(1-√3)²+4-√3 = I1-√3I +4-√3 = √3-1+4-√3 = 3

b = 2√(2√2-3)²+2(3+2√2) = 2·I2√2-3I+2·(3+2√2) =

2√2 = √8 ; 3 = √9 => I2√2-3I = 3-2√2 =>

= 2· (3-2√2)+2·(3+2√2) =2·(3-2√2+3+2√2) = 2·6 = 12

mg (a,b) = √(3·12) = √36 = 6

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c) a = 3-√(√5-3√2)²+√18 = 3-I√5-3√2I+3√2 = 3-3√2+√5-3√2 =

= 3+√5

3√2 = √18 > √5

b = 3-I√7-√20I-√(√5-√7)² = 3-√20+√7-I√5-√7I = 3-2√5+√7-√7+√5 =

= 3-√5

mg (a,b) = √[(3+√5)(3-√5)] = √(9-5) = √4 = 2

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c) a = √(√3-√6)²+√3-1 = I√3-√6I+√3-1 = √6-√3+√3-1 = √6-1

b = √(2√3+√6)²-√12+1 = I2√3+√6I-2√3+1 = 2√3+√6-2√3+1 = √6+1

mg (a,b) = √[(√6-1)(√6+1)] = √(6-1) = √5

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d) a = I√7-3I+(√(√7+3)²+12 = 3-√7+I√7+3I+12 = 3-√7+√7+3+12 = 18

b = I2-√5I-√(√5-3)²-√20+13 = √5-2-I√5-3I-2√5+13 =

= √5-2-3+√5-2√5+13 = 8

mg (a,b) = √(18·8) = √144 = 12