verifică egalitățile următoare, efectuând calculele: 2×25+3×(124+198)=100:2+2×(183+300) 2×(268+147) -49:7=56:7+3×(104+195) 155:5+6×(159+78)=7×(29+112)-144:12 4×(109+125-110:10=2×(199+269)-88:8


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Răspuns:

2×25+3×(124+198)=100:2+2×(183+300)

50+3×322=50+2×483

50+966=50+966

1016=1016

2×(268+147) -49:7=56:7+3×(104+195)

2×415-7=8+3×299

830-7=8+897

823<905

155:5+6×(159+78)=7×(29+112)-144:12

31+6×237=7×141-12

31+1422=987-12

1453>975

4×(109+125)-110:10=2×(199+269)-88:8

4×234-11=2×468-11

936-11=936-11

925=925