Răspuns:
Explicație:
48 g Mg
react. cu HCl
masa de MgCl2
VH2
48g xg xg
Mg + 2HCl = MgCl2 + H2
24g 95g 2g
MMg Cl2= 24 + 2.35,5= 95----> 95g/moli
x= 48 . 95 : 24= 190 g Mg Cl2
n= m : M
n= 190g : 95g/moli= 2 moli MgCl2
y= 48 . 2 : 24 = 4 g H
n= 4g : 2g/moli = 2moli H2
VH2 = 2moli . 22,4 L /moli = 44,8 L