Răspuns:
[tex]\boldsymbol{ \red{x = 6}}[/tex]
[tex]\boldsymbol{ \red{ y = 12 }}[/tex]
Explicație pas cu pas:
[tex]tg 60 = \dfrac{6\sqrt{3} }{x} \Rightarrow \sqrt{3} = \dfrac{6\sqrt{3} }{x} \Rightarrow x = \dfrac{6\sqrt{3} }{\sqrt{3}} \Rightarrow \bf x = 6[/tex]
[tex]\sin 60 = \dfrac{6\sqrt{3} }{y} \Rightarrow \dfrac{\sqrt{3} }{2} = \dfrac{6\sqrt{3} }{y} \Rightarrow y = \dfrac{2 \cdot 6\sqrt{3} }{\sqrt{3}} \Rightarrow \bf y = 12[/tex]
