10×{24^2:576+3×[(3^2×2)^15:(3^29×2^15)+1^21]}:13 =
10×{576:576+3×[(3^30×2^15):(3^29×2^15)+1]} : 13 =
10× [1 + 3 × (3^1 × 1 + 1)] : 13 =
10 × [ 1 + 3 × (3 + 1)] : 13 =
10 × ( 1 + 3 × 4) : 13 =
10 × (1 + 12) : 13 =
10 × 13 : 13 =
10 × 1 =
10
____
^ = simbol folosit ptr ridicarea la putere
24^2 = 24 la puterea 2
iti explic separat, in detaliu, paranteza patrata:
(3^2 × 2)^15 : (3^29 × 2^15) + 1^21=
[(3^2)^15 × 2^15] : (3^29 × 2^15) + 1 =
(3^30 × 2^15) : ( 3^29 × 2^15) + 1=
3^30 : 3^29 × 2^15 : 2^15 + 1 =
3^(30 - 29) × 1 + 1=
3^1 × 1 + 1 =
3 + 1 =
4
