Răspuns
Explicație pas cu pas:
[tex]\left(\dfrac{2}{3}\right)^5\cdot \left(\dfrac{3}{2}\right)^3-\left(\dfrac{1}{2}-\dfrac{1}{3}\right)^2= \\ \left(\dfrac{2}{3}\right)^5\cdot\left(\dfrac{2}{3}\right)^{-3}-\left(\dfrac{3-2}{6}\right)^2= \\ \left(\dfrac{2}{3}\right)^2-\left(\dfrac{1}{6}\right)^2=\\ \dfrac{4}{9}-\dfrac{1}{36}=\\\dfrac{4\cdot 4-1}{36} =\\\dfrac{15}{36}=\dfrac{5}{12}=\dfrac{10}{24}[/tex]
