Cazul 1
Vectorial:F+Ff+G+N=ma1
Scalar;Ox:Fcosα-Ff=ma1
Oy:N+Fsinα-mg=0=>N=mg-Fsinα
Ff=μN=μ(mg-Fsinα)
Fcosα-μmg+μFsinα=ma1=>a1=[Fcosα-μ(mg-Fsinα)]/m=[40*0,866-0,3(10*10-40*0,5)]/10=(34,64-0,3*80)/10=10,64/10=1,064 m/s²
Cazul 2
F+G+N+Ff=ma
Scalar:Ox:Fcosα-Ff=ma
Oy:N-Fsinα-mg=0=>N=-mg-Fsinα
Ff=μN=μ(-mg-Fsinα)
Fcosα-μmg-μFsinα=ma=>a=(Fcosα-μmg-μFsinα)/m=(40*0,866-0,3*10*10-0,3*40*0,5)/10=(34,64-30-6)/10=-1,36/10=-0,136 m/s²
Deoarece a<0=> miscarea este incetinita iar la un moment dat viteza finala va fi 0=>v2=0
