[tex](5 + 2 \sqrt{2)}x + (1 - \sqrt{2)} y = 4 + 3 \sqrt{2} [/tex]
hellllp plsss​


Răspuns :

[tex](5+2\sqrt2)x+(1-\sqrt2)y=4+\srqt2\\5x+2x\sqrt2+y-y\sqrt2=4+3\sqrt2\\5x+y+(2x-y)\sqrt2=4+3\sqrt2\\\displaystyle+\left \{ {{5x+y=4} \atop {2x-y=3}} \right. \\7x=7\Rightarrow x=1\Rightarrow y=-1[/tex]