[tex]\it\Big(\dfrac{11}{12}\Big)^2 =\dfrac{11^2}{12^2}=\dfrac{121}{144}\\ \\ \\ \Big(\dfrac{7}{11}\Big)^0=1\\ \\ \\ \Big(2\dfrac{1}{2}\Big)^4 =\Big(\dfrac{5}{2}\Big)^4=\dfrac{5^4}{2^4}=\dfrac{625}{16}\\ \\ \\ \Big(1\dfrac{2}{3}\Big)^3=\Big(\dfrac{5}{3}\Big)^3=\dfrac{5^3}{3^3}=\dfrac{125}{27}[/tex]