Rezolvati in multimea numerelor reale ecuatia 4^x•8^x+1=16^2x
Ma puteti ajuta?


Răspuns :

[tex] {4}^{x} \times {8}^{x + 1} = {16}^{2x} = > {2}^{2x} \times {2}^{3x + 3} = {2}^{8x} = > {2}^{5x + 3} = {2}^{8x} = > 5x + 3 = 8x = > 5x - 8x = - 3 = > - 3x = - 3 = > x = 1.[/tex]