[tex]\dfrac{24}{25}= \dfrac{25-1}{25} = \dfrac{25}{25} - \dfrac{1}{25} = 1-\dfrac{1}{25}\\ \\\\\dfrac{25}{26} = \dfrac{26-1}{26} = \dfrac{26}{26}-\dfrac{1}{26} = 1-\dfrac{1}{26}\\ \\ \\\text{Cum }\,\dfrac{1}{25}>\dfrac{1}{26} \Rightarrow -\dfrac{1}{25} < -\dfrac{1}{26} \Rightarrow 1-\dfrac{1}{25} < 1-\dfrac{1}{26},\\ \\\\ \text{adic\u{a} }\,\dfrac{24}{25} < \dfrac{25}{26}.[/tex]
