Răspuns:
-ecuatia reactiei de ardere
1mol......................7mol.........4mol
C7H8 + 9O2--->7CO2 + 4H2O
0,3mol...................x................y
x= 2,1molCO2
Y= 1,2mol
m,CO2= niuxM=2,1molx44g/mol=................calculeaza
sau V,CO2= niuxVm= 2,1molx22,4l/mol=.............................calculeaza
m,H2O= niuxM= 1,2molx18g/mol=...............................calculeaza
C6H5-CH3----> TOLUENUL
Explicație:
