Răspuns:
-calculez masa dizolvata de acid din solutei
c=mdx100/ms---> md= 36,5x73/100g=26,6gHCl
-stim: M,HCl= 36,5g/mol AZn=65g/mol Vm= 22,4l/mol
calulez masa de gaz si excesul de substanta din ecuatia chimica
1 mol 2mol 1mol
Zn + 2HCl------> ZnCl2 + H2
65g........2x36,5g,,,,,,,..............22,4l
6,5g..................x......................y
x= 73/10g=7,3gHCl acesta este in exces cu (26,6-7,3)g=19,3g
y= 6,5x22,4/65 l=2,24 l