1.2x(x-y) +3y(x-y) =
2.x(x+1)-2(x+1)=
3.x(x-1)^2-2x(x-1)=
4.a^2(a+b) +b^2(a+b) =
5.(a-2)x-(a-2)y+a-2 =
6.(3x-2y) (2x+5y) -(x-3y) (2x+5y) =

Presupun ca trebuia sa dai factor comun.

1.(x-y)*(2*x-3*y)

2.(x+1)*(x-2)

3.(x-1)*[x*(x-1)-2*x]

4.(a+b)*(a^2+b^2)

5.(a-2)*(x-y+1)

6.(2*x+5*y)*(3*x-2*y-x+3*y)=(2*x+5*y)*(2*x+y)

Răspuns:

1)

[tex]2 {x}^{2} - 2xy + 3xy - 3 {y}^{2} = 2 {x}^{2} + xy - 3 {y}^{2} [/tex]

2)

[tex](x + 1)(x - 2) = {x}^{2} - 2x + x - 2 = {x}^{2} - x - 2[/tex]

3)

[tex](x - 1)(x(x - 1) - 2x) = (x - 1)( {x}^{2} - x - 2x) = (x - 1)( {x}^{2} - 3x)[/tex]

4)

[tex](a + b)( {a}^{2} + {b}^{2} ) = {a}^{3} + a {b}^{2} + {a}^{2} b + {b}^{3} [/tex]

Cam asa se rezolvă