Efectuați:
a)x+5 supra3 + 2x-7 supra 3
b)x-1 supra 2 + x+5 supra 3
c) 7x+5 supra 5 -2x+9 supra 4
d)2x+1 supra 4 - 2x-1 supra 6
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Dacă nu ai inteles raționamentul ti le pot face si pe celalalte 2

[tex]\displaystyle\bf\\a)\\\frac{x+5}{3}+\frac{2x-7}{3}=\frac{x+5+2x-7}{3}=\boxed{\bf\frac{3x-2}{3}}\\\\\\b)\\\frac{x-1}{2}+\frac{x+5}{3}=\frac{3(x-1)}{6}+\frac{2(x+5)}{6}=\\\\=\frac{3x-3+2x+10}{6}=\boxed{\bf\frac{5x+7}{6}}\\\\\\c)\\\frac{7x+5}{5}-\frac{2x+9}{4}=\frac{4(7x+5)}{20}-\frac{5(2x+9)}{20}=\\\\=\frac{28x+20-10x-45}{20}=\boxed{\bf\frac{18x-25}{20}}\\\\\\d)\\\frac{2x+1}{4}-\frac{2x-1}{6}=\frac{3(2x+1)}{12}-\frac{2(2x-1)}{12}=\\\\=\frac{6x+3-4x+2}{12}=\boxed{\bf\frac{2x+5}{12}}[/tex]