efectuați
a) 2 radical 3 +5radical 3+radical 48
b)MINUS 7RADICAL 2 +3 RADICAL 18 MMINUS 5 RADICAL 2​

Răspuns:

a)7rad3 +4rad 3=11rad3

b)-7rad.2+9rad.2-5rad.2 (am scis de sub rad la 18)

-3rad.2

Răspuns:

a)

[tex]2 \sqrt{3} + 5 \sqrt{3} + \sqrt{48} \\ \sqrt{48} = 4 \sqrt{3} \\ 2 \sqrt{3} + 5 \sqrt{3} + 4 \sqrt{3} = 11 \sqrt{3} [/tex]

b)

[tex] - 7 \sqrt{2} + 3 \sqrt{18} - 5 \sqrt{2} \\ 3 \sqrt{18} = 9 \sqrt{2} \\ - 7 \sqrt{2} + 9 \sqrt{2} - 5 \sqrt{2} = - 3 \sqrt{2} [/tex]

succes! :)