Vă rog!Ex 5 tot,dau coroană​

Răspuns:

a)x²=16·9=>x²=144=>x=±√144=>x=±12

b)x²=3/2=>x=±[tex]\sqrt{3/2}[/tex]

c)x²=10/9=>x=±[tex]\sqrt{10/9}[/tex]=>x=±√10/3

d)x²=0,5/4=>x=±[tex]\sqrt{0.5/4}[/tex]=>x=±√0.5/2

e)64x²=100=>x²=100/64=>x=±[tex]\sqrt{100/64}[/tex]=>x=±5/4

f)x²=7/3=>x=±[tex]\sqrt{7/3}[/tex]

g)x²=32/25=>x=±[tex]\sqrt{32/25}[/tex]=>x=±√32/5

h)x²=25/144=>x=±[tex]\sqrt{25/144}[/tex]=>x=±5/12

i)x²=12.25=>x=±√12.25=>x=±[tex]\sqrt{1225/100}[/tex]=>x=±35/10

=>x=±7/2

j)x²=11/4=>x=±[tex]\sqrt{11/4}[/tex]=>x=±√11/2

k)x²=24/29=>x=±[tex]\sqrt{24/49}[/tex]=>x=±(2√6)/7

l)0,(3)=3/9=1/3

 9x²-1=0=>9x²=1=>x²=1/9=>x=±[tex]\sqrt{1/9}[/tex]=>x=±1/3

x²/9 = 16

x² = 16×9

x² = 4²×3²

x = 4×3

x = ±12

2x² = 3

x² = 3/2

x = √(3/2)

x = ±√6/2

9x² - 10 = 0

9x² = 10

x² = 10/9

x = ±(√10)/3

4x² = 0,5

x² = (1/2)/4

x² = 1/2×1/4

x² = 1/8

x = 1/√8

x = 1/2√2

x = ±√2/4

x²/100 - 1/64 = 0

x²/100 = 1/64

x² = 100/64

x = 10/8

x = ±5/4

3x² = 7

x² = 7/3

x = √(7/3)

x = ±√21/3

25x² - 32 = 0

25x² = 32

x² = 32/25

x = √32/5

x = √2⁵/5

x = ±4√2/5

144x² = 25

x² = 25/144

x = ±5/12

x²/25 = 49/100

x² = 25×49/100

x = 5×7/10

x = 35/10

x = ±7/2

4x² = 11

x² = 11/4

x = ±(√11)/2

49x² = 24

x² = 24/49

x = √24/7

x = √2³×3/7

x = ±2√6/7

3x² = 1/3

x² = 1/3×1/3

x² = 1/9

x = ±1/3